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| Re: OT: How much force in "pounds" do you think..... [message #71743 is a reply to message #71742] |
Fri, 25 August 2006 12:31   |
Nil
Messages: 245
Registered: March 2007
|
Senior Member |
|
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What if you got a fish-weighing scale, attached it with an
eye-hook to the wall behind the beater then attached a
wire/cable connecting the scale to the beater itself, then
whacked away? Film the scale with a high-speed IMAX camera, then
review frame by frame until you find the one with the maximum
deflection on the scale, and there you have it!
:)
(Just trying to find the most DJ-esque solution to the problem)
"Tony Benson" <tony@standinghampton.com> wrote:
>Hum? I'm not a physics dude, but I think besides just the deflection of
the
>head, you'd have to account for the velocity of the beater head,etc. I'm
>just not sure if you can equate a static weight on the head with the actual
>force of a moving beater hitting it for a split second. I know several real
>smart math and electronics nerds (PhD types), but no physics docs. I might
>check around and see if I can find someone who can tell me how to figure
>this out. Now where did I put that dang accelerometer? ;>)
>
>Tony
>
>
>
>"Brandon" <a@a.com> wrote in message news:44ef3c45@linux...
>> Well I was thinking of how much the head moves inward when the beater
hits
>> it.
>> I was thinking maybe 1"-2". So, if I took the bass drum and turned it
on
>> its
>> side
>> and placed a 20 pound weight focused down to a 1 square inch area in the
>> center of the drum head I think it would displace the drum head by at
>> least
>> 1 1/2".
>> So wouldn't that be equivalent? Perhaps its a little more 30 or 40.
>>
>>
>> --
>> Brandon
>>
>>
>> "Tony Benson" <tony@standinghampton.com> wrote in message
>> news:44ef3868@linux...
>>> I think it'd be much higher myself. You'd have to measure in pounds per
>>> square inch also for the measure to have much meaning. Since the beater
>> head
>>> is probably only contacting a little over 1 square inch, I'm guessing
a
>> good
>>> hard hit will be pretty substantial. Now you got me wondering.
>>>
>>> Tony
>>>
>>>
>>> "Brandon" <a@a.com> wrote in message news:44ef162d$1@linux...
>>> > The solenoid is for work. Trying to make an upgrade to our electronics
>>> > production line.
>>> >
>>> > The kick question came up last night at the studio with my friends
band
>>> > and
>>> > now I am curious.
>>> > I am guessing around 20 pounds.
>>> >
>>> >
>>> > --
>>> > Brandon
>>> >
>>> >
>>> > "Neil" <OIUOIU@OIU.com> wrote in message news:44ef107e$1@linux...
>>> >>
>>> >> Trying to make a robotic kick drum, are ya? :)
>>> >>
>>> >> Is that why you needed the solenoid?
>>> >>
>>> >> Neil
>>> >>
>>> >>
>>> >> "Brandon" <a@a.com> wrote:
>>> >> >
>>> >> >
>>> >> >How much force in "pounds" do you think is applied to=20
>>> >> >
>>> >> >a kick drum from the beater hitting the head? (range)
>>> >> >
>>> >> >
>>> >> >
>>> >> >Thanks
>>> >> >
>>> >> >
>>> >> >--=20
>>> >> >Brandon
>>> >> >
>>> >> ><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
>>> >> ><HTML><HEAD>
>>> >> ><META http-equiv=3DContent-Type content=3D"text/html; =
>>> >> >charset=3Diso-8859-1">
>>> >> ><META content=3D"MSHTML 6.00.2800.1476" name=3DGENERATOR>
>>> >> ><STYLE></STYLE>
>>> >> ></HEAD>
>>> >> ><BODY bgColor=3D#ffffff>
>>> >> ><DIV><FONT face=3DArial><FONT size=3D1>
>>> >> ><P>How much force in "pounds" do you think is applied to </P>
>>> >> ><P>a kick drum from the beater hitting the head? (range)</P>
>>> >> ><P> </P>
>>> >> ><P><FONT size=3D3>Thanks</FONT></P></FONT></FONT></DIV><FONT =
>>> >> >face=3DArial>
>>> >> ><DIV><BR>-- <BR>Brandon </FONT></DIV></BODY></HTML>
>>> >> >
>>> >> >
>>> >>
>>> >
>>> >
>>>
>>>
>>
>>
>
>
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| Re: OT: How much force in "pounds" do you think..... [message #71744 is a reply to message #71743] |
Fri, 25 August 2006 13:16 |
Tony Benson
Messages: 453
Registered: June 2006
|
Senior Member |
|
|
Hah! Deej Goldberg! I like it!
I'm sure there's some kind of all-in-one device out there that would measure
this actually.
Tony
"Neil" <IUOIU@OIU.com> wrote in message news:44ef5007$1@linux...
>
> What if you got a fish-weighing scale, attached it with an
> eye-hook to the wall behind the beater then attached a
> wire/cable connecting the scale to the beater itself, then
> whacked away? Film the scale with a high-speed IMAX camera, then
> review frame by frame until you find the one with the maximum
> deflection on the scale, and there you have it!
>
> :)
> (Just trying to find the most DJ-esque solution to the problem)
>
>
>
>
>
> "Tony Benson" <tony@standinghampton.com> wrote:
>>Hum? I'm not a physics dude, but I think besides just the deflection of
> the
>>head, you'd have to account for the velocity of the beater head,etc. I'm
>
>>just not sure if you can equate a static weight on the head with the
>>actual
>
>>force of a moving beater hitting it for a split second. I know several
>>real
>
>>smart math and electronics nerds (PhD types), but no physics docs. I might
>
>>check around and see if I can find someone who can tell me how to figure
>
>>this out. Now where did I put that dang accelerometer? ;>)
>>
>>Tony
>>
>>
>>
>>"Brandon" <a@a.com> wrote in message news:44ef3c45@linux...
>>> Well I was thinking of how much the head moves inward when the beater
> hits
>>> it.
>>> I was thinking maybe 1"-2". So, if I took the bass drum and turned it
> on
>>> its
>>> side
>>> and placed a 20 pound weight focused down to a 1 square inch area in the
>>> center of the drum head I think it would displace the drum head by at
>
>>> least
>>> 1 1/2".
>>> So wouldn't that be equivalent? Perhaps its a little more 30 or 40.
>>>
>>>
>>> --
>>> Brandon
>>>
>>>
>>> "Tony Benson" <tony@standinghampton.com> wrote in message
>>> news:44ef3868@linux...
>>>> I think it'd be much higher myself. You'd have to measure in pounds per
>>>> square inch also for the measure to have much meaning. Since the beater
>>> head
>>>> is probably only contacting a little over 1 square inch, I'm guessing
> a
>>> good
>>>> hard hit will be pretty substantial. Now you got me wondering.
>>>>
>>>> Tony
>>>>
>>>>
>>>> "Brandon" <a@a.com> wrote in message news:44ef162d$1@linux...
>>>> > The solenoid is for work. Trying to make an upgrade to our
>>>> > electronics
>>>> > production line.
>>>> >
>>>> > The kick question came up last night at the studio with my friends
> band
>>>> > and
>>>> > now I am curious.
>>>> > I am guessing around 20 pounds.
>>>> >
>>>> >
>>>> > --
>>>> > Brandon
>>>> >
>>>> >
>>>> > "Neil" <OIUOIU@OIU.com> wrote in message news:44ef107e$1@linux...
>>>> >>
>>>> >> Trying to make a robotic kick drum, are ya? :)
>>>> >>
>>>> >> Is that why you needed the solenoid?
>>>> >>
>>>> >> Neil
>>>> >>
>>>> >>
>>>> >> "Brandon" <a@a.com> wrote:
>>>> >> >
>>>> >> >
>>>> >> >How much force in "pounds" do you think is applied to=20
>>>> >> >
>>>> >> >a kick drum from the beater hitting the head? (range)
>>>> >> >
>>>> >> >
>>>> >> >
>>>> >> >Thanks
>>>> >> >
>>>> >> >
>>>> >> >--=20
>>>> >> >Brandon
>>>> >> >
>>>> >> ><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
>>>> >> ><HTML><HEAD>
>>>> >> ><META http-equiv=3DContent-Type content=3D"text/html; =
>>>> >> >charset=3Diso-8859-1">
>>>> >> ><META content=3D"MSHTML 6.00.2800.1476" name=3DGENERATOR>
>>>> >> ><STYLE></STYLE>
>>>> >> ></HEAD>
>>>> >> ><BODY bgColor=3D#ffffff>
>>>> >> ><DIV><FONT face=3DArial><FONT size=3D1>
>>>> >> ><P>How much force in "pounds" do you think is applied to </P>
>>>> >> ><P>a kick drum from the beater hitting the head? (range)</P>
>>>> >> ><P> </P>
>>>> >> ><P><FONT size=3D3>Thanks</FONT></P></FONT></FONT></DIV><FONT =
>>>> >> >face=3DArial>
>>>> >> ><DIV><BR>-- <BR>Brandon </FONT></DIV></BODY></HTML>
>>>> >> >
>>>> >> >
>>>> >>
>>>> >
>>>> >
>>>>
>>>>
>>>
>>>
>>
>>
>
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| Re: OT: How much force in "pounds" do you think..... [message #71748 is a reply to message #71743] |
Fri, 25 August 2006 15:50 |
Deej [1]
Messages: 2149
Registered: January 2006
|
Senior Member |
|
|
ROTFL!!!! I love it!!
"Neil" <IUOIU@OIU.com> wrote in message news:44ef5007$1@linux...
>
> What if you got a fish-weighing scale, attached it with an
> eye-hook to the wall behind the beater then attached a
> wire/cable connecting the scale to the beater itself, then
> whacked away? Film the scale with a high-speed IMAX camera, then
> review frame by frame until you find the one with the maximum
> deflection on the scale, and there you have it!
>
> :)
> (Just trying to find the most DJ-esque solution to the problem)
>
>
>
>
>
> "Tony Benson" <tony@standinghampton.com> wrote:
> >Hum? I'm not a physics dude, but I think besides just the deflection of
> the
> >head, you'd have to account for the velocity of the beater head,etc. I'm
>
> >just not sure if you can equate a static weight on the head with the
actual
>
> >force of a moving beater hitting it for a split second. I know several
real
>
> >smart math and electronics nerds (PhD types), but no physics docs. I
might
>
> >check around and see if I can find someone who can tell me how to figure
>
> >this out. Now where did I put that dang accelerometer? ;>)
> >
> >Tony
> >
> >
> >
> >"Brandon" <a@a.com> wrote in message news:44ef3c45@linux...
> >> Well I was thinking of how much the head moves inward when the beater
> hits
> >> it.
> >> I was thinking maybe 1"-2". So, if I took the bass drum and turned it
> on
> >> its
> >> side
> >> and placed a 20 pound weight focused down to a 1 square inch area in
the
> >> center of the drum head I think it would displace the drum head by at
>
> >> least
> >> 1 1/2".
> >> So wouldn't that be equivalent? Perhaps its a little more 30 or 40.
> >>
> >>
> >> --
> >> Brandon
> >>
> >>
> >> "Tony Benson" <tony@standinghampton.com> wrote in message
> >> news:44ef3868@linux...
> >>> I think it'd be much higher myself. You'd have to measure in pounds
per
> >>> square inch also for the measure to have much meaning. Since the
beater
> >> head
> >>> is probably only contacting a little over 1 square inch, I'm guessing
> a
> >> good
> >>> hard hit will be pretty substantial. Now you got me wondering.
> >>>
> >>> Tony
> >>>
> >>>
> >>> "Brandon" <a@a.com> wrote in message news:44ef162d$1@linux...
> >>> > The solenoid is for work. Trying to make an upgrade to our
electronics
> >>> > production line.
> >>> >
> >>> > The kick question came up last night at the studio with my friends
> band
> >>> > and
> >>> > now I am curious.
> >>> > I am guessing around 20 pounds.
> >>> >
> >>> >
> >>> > --
> >>> > Brandon
> >>> >
> >>> >
> >>> > "Neil" <OIUOIU@OIU.com> wrote in message news:44ef107e$1@linux...
> >>> >>
> >>> >> Trying to make a robotic kick drum, are ya? :)
> >>> >>
> >>> >> Is that why you needed the solenoid?
> >>> >>
> >>> >> Neil
> >>> >>
> >>> >>
> >>> >> "Brandon" <a@a.com> wrote:
> >>> >> >
> >>> >> >
> >>> >> >How much force in "pounds" do you think is applied to=20
> >>> >> >
> >>> >> >a kick drum from the beater hitting the head? (range)
> >>> >> >
> >>> >> >
> >>> >> >
> >>> >> >Thanks
> >>> >> >
> >>> >> >
> >>> >> >--=20
> >>> >> >Brandon
> >>> >> >
> >>> >> ><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
> >>> >> ><HTML><HEAD>
> >>> >> ><META http-equiv=3DContent-Type content=3D"text/html; =
> >>> >> >charset=3Diso-8859-1">
> >>> >> ><META content=3D"MSHTML 6.00.2800.1476" name=3DGENERATOR>
> >>> >> ><STYLE></STYLE>
> >>> >> ></HEAD>
> >>> >> ><BODY bgColor=3D#ffffff>
> >>> >> ><DIV><FONT face=3DArial><FONT size=3D1>
> >>> >> ><P>How much force in "pounds" do you think is applied to </P>
> >>> >> ><P>a kick drum from the beater hitting the head? (range)</P>
> >>> >> ><P> </P>
> >>> >> ><P><FONT size=3D3>Thanks</FONT></P></FONT></FONT></DIV><FONT =
> >>> >> >face=3DArial>
> >>> >> ><DIV><BR>-- <BR>Brandon </FONT></DIV></BODY></HTML>
> >>> >> >
> >>> >> >
> >>> >>
> >>> >
> >>> >
> >>>
> >>>
> >>
> >>
> >
> >
>
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